If the coordinates of one end of the diameter of the circle $x^2 + y^2 - 8x - 4y + c = 0$ are $(-3, 2)$,then the coordinates of the other end are:

  • A
    $(5, 3)$
  • B
    $(6, 2)$
  • C
    $(1, -8)$
  • D
    $(11, 2)$

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