If the dimensions of a physical quantity are | vedclass

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(C) The dimensions of a physical quantity are given as $[L^{a} M^{b} T^{c}]$.Let us check the dimensions of the given options:$1$. Velocity: $[M^{0} L

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pressure if $a=-1, b=1, c=-2$

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(C) The dimensions of a physical quantity are given as $[L^{a} M^{b} T^{c}]$.Let us check the dimensions of the given options:$1$. Velocity: $[M^{0} L^{1} T^{-1}]$. Here,$a=1, b=0, c=-1$. Option $A$ is incorrect.$2$. Force: $[M^{1} L^{1} T^{-2}]$. Here,$a=1, b=1, c=-2$. Option $B$ is incorrect.$3$. Pressure: Pressure is defined as $	ext{Force} / 	ext{Area} = [M^{1} L^{1} T^{-2}] / [L^{2}] = [M^{1} L^{-1} T^{-2}]$. Here,$a=-1, b=1, c=-2$. This matches option $C$.$4$. Acceleration: $[M^{0} L^{1} T^{-2}]$. Here,$a=1, b=0, c=-2$. Option $D$ is incorrect.Therefore,the correct option is $C$.

List-$I$	List-$II$
$A$. Coefficient of viscosity	$I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension	$II$. $[ML^2T^{-2}]$
$C$. Pressure	$III$. $[ML^0T^{-2}]$
$D$. Surface energy	$IV$. $[ML^{-1}T^{-1}]$

If the dimensions of a physical quantity are given by $[L^{a} M^{b} T^{c}]$,then the physical quantity is:

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If $M =$ mass,$L =$ length,$T =$ time,and $I =$ electric current,then the dimensional formula for electrical resistance $R$ is:

The dimensions of pressure are

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. Coefficient of viscosity $I$. $[ML^{-1}T^{-2}]$
$B$. Surface tension $II$. $[ML^2T^{-2}]$
$C$. Pressure $III$. $[ML^0T^{-2}]$
$D$. Surface energy $IV$. $[ML^{-1}T^{-1}]$

Choose the correct answer from the options given below:

The expression $[M{L^2}{T^{ - 2}}]$ represents

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