If the equation x^4+7x^3+18x^2+20x+8=0 has a | vedclass

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(A) Given equation is $x^4+7x^3+18x^2+20x+8=0$. We can factorize the polynomial by testing small integer roots. For $x = -2$: $(-2)^4 + 7(-2)^3 + 18(-

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$-2$

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(A) Given equation is $x^4+7x^3+18x^2+20x+8=0$. We can factorize the polynomial by testing small integer roots. For $x = -2$: $(-2)^4 + 7(-2)^3 + 18(-2)^2 + 20(-2) + 8 = 16 - 56 + 72 - 40 + 8 = 0$. So,$(x+2)$ is a factor. Dividing $x^4+7x^3+18x^2+20x+8$ by $(x+2)$ gives $x^3+5x^2+8x+4$. Testing $x = -2$ again for $x^3+5x^2+8x+4$: $(-2)^3 + 5(-2)^2 + 8(-2) + 4 = -8 + 20 - 16 + 4 = 0$. So,$(x+2)$ is a factor again. Dividing $x^3+5x^2+8x+4$ by $(x+2)$ gives $x^2+3x+2 = (x+1)(x+2)$. Thus,the equation is $(x+2)^3(x+1) = 0$. The repeated root is $-2$.

If the equation $x^4+7x^3+18x^2+20x+8=0$ has a repeated root,then that repeated root is

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