If the equivalent capacitance between points $A$ and $B$ of the combination of capacitors shown in the figure is $6C$, then the capacitor $C^1$ is: (in $C$)

Two capacitors $C_1 = 2 \,\mu F$ and $C_2 = 6 \,\mu F$ are connected in series. This combination is then connected in parallel with a third capacitor $C_3 = 4 \,\mu F$. This entire arrangement is connected to a battery of $2 \,V$. What is the energy supplied by the battery to charge the capacitors?

Find the equivalent capacitance between two points $A$ and $B$ for the given circuit. (Capacitance of each capacitor is $C = 3 \mu F$.) (in $\mu F$)

Three capacitors of $2\ \mu F, 3\ \mu F$,and $6\ \mu F$ are connected in series with a $24\ V$ battery. The potential difference across the $6\ \mu F$ capacitor is .......... $V$.

Two capacitors having capacitances $8 \mu F$ and $16 \mu F$ have breaking voltages $20 \ V$ and $80 \ V$ respectively. They are connected in series. What is the maximum charge they can store in this combination in $\mu C$?

What is the equivalent capacitance between points $A$ and $B$ in the given circuit?