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(A) The frequency of the carrier wave is $f_c = 1 	ext{ MHz} = 1000 	ext{ kHz}$.The frequency of the message signal is $f_m = 28 	ext{ kHz}$.The fr

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$1028 	ext{ kHz}, 972 	ext{ kHz}$

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(A) The frequency of the carrier wave is $f_c = 1 	ext{ MHz} = 1000 	ext{ kHz}$.The frequency of the message signal is $f_m = 28 	ext{ kHz}$.The frequencies of the side bands are given by the upper side band $(USB)$ and lower side band $(LSB)$ formulas:$USB = f_c + f_m = 1000 	ext{ kHz} + 28 	ext{ kHz} = 1028 	ext{ kHz}$.$LSB = f_c - f_m = 1000 	ext{ kHz} - 28 	ext{ kHz} = 972 	ext{ kHz}$.Therefore,the side band frequencies are $1028 	ext{ kHz}$ and $972 	ext{ kHz}$.

If the frequencies of the carrier wave and message signal are $1 \text{ MHz}$ and $28 \text{ kHz}$ respectively,then the frequencies of the side bands are

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