If the frequency of the source e.m.f. in an a | vedclass

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(B) The instantaneous voltage in an $ac$ circuit is given by $V = V_0 \sin(\omega t),$ where $\omega = 2\pi n$ and $n$ is the frequency of the source.

Vedclass · Accepted Answer

$2n$

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(B) The instantaneous voltage in an $ac$ circuit is given by $V = V_0 \sin(\omega t),$ where $\omega = 2\pi n$ and $n$ is the frequency of the source.The instantaneous power $P$ in the circuit is given by $P = V \cdot I = V_0 \sin(\omega t) \cdot I_0 \sin(\omega t + \phi) = V_0 I_0 \sin(\omega t) \sin(\omega t + \phi).$Using the trigonometric identity $\sin A \sin B = \frac{1}{2} [\cos(A-B) - \cos(A+B)],$ we get:$P = \frac{V_0 I_0}{2} [\cos(\phi) - \cos(2\omega t + \phi)].$Since the power expression contains a term with $2\omega,$ the frequency of the power variation is $2n.$

If the frequency of the source $e.m.f.$ in an $ac$ circuit is $n,$ the power varies with a frequency :-

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