The output of a step-down transformer is measured to be $24 \ V$,when connected to a $12 \ W$ light bulb. The value of peak current is $...... \ A$. (in $A$)

If an alternating current is given by $i = a \sin(\omega t) + b \cos(\omega t)$,then the $rms$ value of the current is

For an $AC$ current $I = 50 \cos(100t + 45^{\circ}) \ A$. The value of $I_{rms} =$ . . . . . . $A$.

In an $A.C.$ circuit,the instantaneous current and $E.M.F.$ are represented as $i = i_0 \sin(\omega t - \frac{\pi}{6})$ and $E = E_0 \sin(\omega t + \frac{\pi}{3})$ respectively. The voltage leads the current by

In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be

Both alternating current and direct current are measured in amperes. But how is the ampere defined for an alternating current?