If the internal energy of 3 moles of a gas at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The internal energy $U$ of $n$ moles of an ideal gas is given by the formula: $U = \frac{f}{2} n R T$,where $f$ is the number of degrees of freedo

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) The internal energy $U$ of $n$ moles of an ideal gas is given by the formula: $U = \frac{f}{2} n R T$,where $f$ is the number of degrees of freedom,$n$ is the number of moles,$R$ is the universal gas constant,and $T$ is the absolute temperature in Kelvin.Given: $n = 3$,$T = 27^{\circ} C = 27 + 273 = 300 \ K$,and $U = 2250 R$.Substituting these values into the formula:$2250 R = \frac{f}{2} 	imes 3 	imes R 	imes 300$$2250 = \frac{f}{2} 	imes 900$$2250 = f 	imes 450$$f = \frac{2250}{450} = 5$.Therefore,the number of degrees of freedom of the gas is $5$.

If the internal energy of $3$ moles of a gas at a temperature of $27^{\circ} C$ is $2250 R$,then the number of degrees of freedom of the gas is (where $R$ is the universal gas constant).

Similar Questions

The total thermal energy associated with $200 \, g$ of oxygen at $27 \, ^\circ C$ is ......... $J$. (Assume oxygen molecules as rigid rotators.)

When heat is supplied to an Argon gas,what is the percentage distribution of the energy into translational and rotational kinetic energy?

According to the law of equipartition of energy, the molar specific heat of a non-rigid diatomic gas at constant volume is

The total number of degrees of freedom in $1 \ cm^3$ of $H_2$ gas at $NTP$ is ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module