If the longitudinal strain of a stretched wir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The longitudinal strain is given by $\epsilon_L = 0.2 \% = 0.002$.Poisson's ratio $\sigma$ is defined as the ratio of lateral strain $\epsilon_d$

Vedclass · Accepted Answer

$0.08$

Vedclass · Answer

(B) The longitudinal strain is given by $\epsilon_L = 0.2 \% = 0.002$.Poisson's ratio $\sigma$ is defined as the ratio of lateral strain $\epsilon_d$ to longitudinal strain $\epsilon_L$,so $\epsilon_d = -\sigma \cdot \epsilon_L$.Here,$\sigma = 0.3$,so the lateral strain is $\epsilon_d = -0.3 	imes 0.002 = -0.0006$.The volume strain $\frac{\Delta V}{V}$ for a wire is given by the sum of longitudinal strain and two lateral strains: $\frac{\Delta V}{V} = \epsilon_L + 2\epsilon_d$.Substituting the values: $\frac{\Delta V}{V} = 0.002 + 2(-0.0006) = 0.002 - 0.0012 = 0.0008$.Converting to percentage: $0.0008 	imes 100 \% = 0.08 \%$.

If the longitudinal strain of a stretched wire is $0.2 \%$ and the Poisson's ratio of the material of the wire is $0.3$,then the volume strain of the wire is (in $\%$)

Similar Questions

For a given material, the Young's modulus is $2.4$ times its modulus of rigidity. Its Poisson's ratio is ......

$A$ material has Poisson's ratio $0.5$. If a uniform rod of it suffers a longitudinal strain of $3 \times 10^{-3}$, what will be the percentage increase in volume? .......... $\%$

What is Poisson's ratio? On what does its magnitude depend?

Liquids have no Poisson's ratio,because

The possible value of Poisson's ratio is

Vedclass Test Series

Exam Paper Generator

Online Exam Module