If the mid-points of the sides BC,CA and AB o | vedclass

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(B) Let the mid-points be $P(2,1)$ on $BC$,$Q(-1,-2)$ on $CA$,and $R(3,3)$ on $AB$.Since $RQ$ is parallel to $BC$ and $RQ = \frac{1}{2} BC$,the side $

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$5x-4y=6$

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(B) Let the mid-points be $P(2,1)$ on $BC$,$Q(-1,-2)$ on $CA$,and $R(3,3)$ on $AB$.Since $RQ$ is parallel to $BC$ and $RQ = \frac{1}{2} BC$,the side $BC$ is parallel to the line segment $RQ$.The slope of $RQ$ is $m = \frac{3 - (-2)}{3 - (-1)} = \frac{5}{4}$.Since $BC$ is parallel to $RQ$,the slope of $BC$ is also $m = \frac{5}{4}$.The side $BC$ passes through the point $P(2,1)$.Using the point-slope form,the equation of $BC$ is:$y - 1 = \frac{5}{4}(x - 2)$$4(y - 1) = 5(x - 2)$$4y - 4 = 5x - 10$$5x - 4y = 6$

If the mid-points of the sides $BC$,$CA$ and $AB$ of a triangle $ABC$ are respectively $(2,1)$,$(-1,-2)$ and $(3,3)$,then the equation of the side $BC$ is

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