If the output of a NAND gate is given as inpu | vedclass

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(A) $NAND$ gate performs the operation $Y = \overline{A \cdot B}$.When this output is fed into a $NOT$ gate, the final output becomes $Y' = \overline{

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$AND$

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(A) $NAND$ gate performs the operation $Y = \overline{A \cdot B}$.When this output is fed into a $NOT$ gate, the final output becomes $Y' = \overline{Y} = \overline{(\overline{A \cdot B})}$.By the law of double negation, $\overline{(\overline{X})} = X$. Therefore, $Y' = A \cdot B$.This is the Boolean expression for an $AND$ gate.Input $(A, B)$$NAND$ Output $(\overline{A \cdot B})$$NOT$ Output $(A \cdot B)$$0, 0$$1$$0$$0, 1$$1$$0$$1, 0$$1$$0$$1, 1$$0$$1$

If the output of a $NAND$ gate is given as input to a $NOT$ gate, the resultant gate is

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