If the planes 2x - 5y + z = 8 and 2lambda x - | vedclass

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(D) Two planes $a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$ are parallel if their normal vectors are proportional,i.e.,$\frac{a_1

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$3$

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(D) Two planes $a_1x + b_1y + c_1z + d_1 = 0$ and $a_2x + b_2y + c_2z + d_2 = 0$ are parallel if their normal vectors are proportional,i.e.,$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$.Given planes are $2x - 5y + z - 8 = 0$ and $2\lambda x - 15y + \lambda z + 6 = 0$.Comparing the coefficients,we get:$\frac{2}{2\lambda} = \frac{-5}{-15} = \frac{1}{\lambda}$.Simplifying the ratios:$\frac{1}{\lambda} = \frac{1}{3} = \frac{1}{\lambda}$.From this,we conclude that $\lambda = 3$.

If the planes $2x - 5y + z = 8$ and $2\lambda x - 15y + \lambda z + 6 = 0$ are parallel to each other,then the value of $\lambda$ is:

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