If the probability density function of a continuous random variable $X$ is $f(x) = \frac{x^3}{3}$ for $-1 < x < 2$,and $f(x) = 0$ otherwise,then the cumulative distribution function $F(x)$ for $-1 < x < 2$ is:
- A$\frac{1}{14}(x^4 - 1)$
- B$\frac{1}{10}(x^4 - 1)$
- C$\frac{1}{12}(x^4 - 1)$
- D$\frac{1}{16}(x^4 - 1)$
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DifficultMHT CET 2024
View SolutionState whether the following table represents a probability distribution of a random variable $X$. Give reasons for your answer.
$X$ $0$ $1$ $2$ $P(X)$ $0.4$ $0.4$ $0.2$
| $X$ | $0$ | $1$ | $2$ |
| $P(X)$ | $0.4$ | $0.4$ | $0.2$ |
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DifficultMHT CET 2026
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