If the product of the roots of the equation m | vedclass

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(C) For a quadratic equation of the form $ax^2 + bx + c = 0$,the product of the roots is given by the formula $\frac{c}{a}$.In the given equation $mx^

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$\frac{1}{3}$

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(C) For a quadratic equation of the form $ax^2 + bx + c = 0$,the product of the roots is given by the formula $\frac{c}{a}$.In the given equation $mx^2 + 6x + (2m - 1) = 0$,we have $a = m$,$b = 6$,and $c = 2m - 1$.According to the problem,the product of the roots is $-1$.Therefore,$\frac{2m - 1}{m} = -1$.Multiplying both sides by $m$,we get $2m - 1 = -m$.Adding $m$ to both sides,we get $3m - 1 = 0$.Adding $1$ to both sides,we get $3m = 1$.Dividing by $3$,we get $m = \frac{1}{3}$.

If the product of the roots of the equation $mx^2 + 6x + (2m - 1) = 0$ is $-1$,then the value of $m$ will be:

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