If the radioactive decay constant of radium i | vedclass

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Question

(C) The half-life period $T_{1/2}$ of a radioactive substance is related to the decay constant $\lambda$ by the formula: $T_{1/2} = \frac{0.693}{\lamb

Vedclass · Accepted Answer

$6476$

Vedclass · Answer

(C) The half-life period $T_{1/2}$ of a radioactive substance is related to the decay constant $\lambda$ by the formula: $T_{1/2} = \frac{0.693}{\lambda}$.Given the decay constant $\lambda = 1.07 	imes 10^{-4} 	ext{ year}^{-1}$.Substituting the value into the formula:$T_{1/2} = \frac{0.693}{1.07 	imes 10^{-4}}$$T_{1/2} = \frac{0.693}{1.07} 	imes 10^4$$T_{1/2} \approx 0.6476 	imes 10^4 = 6476 	ext{ years}$.Thus,the half-life period is $6476 	ext{ years}$.

If the radioactive decay constant of radium is $1.07 \times 10^{-4}$ per year,then its half-life period is approximately equal to ......... $years$.

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