If the refractive indices of crown glass for | vedclass

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(A) The dispersive power $\omega$ is given by the formula $\omega = \frac{n_v - n_r}{n_y - 1}$,where $n_v, n_r$,and $n_y$ are the refractive indices f

Vedclass · Accepted Answer

$0.034$ and $0.064$

Vedclass · Answer

(A) The dispersive power $\omega$ is given by the formula $\omega = \frac{n_v - n_r}{n_y - 1}$,where $n_v, n_r$,and $n_y$ are the refractive indices for violet,red,and yellow colours respectively.For crown glass:$\omega_{	ext{crown}} = \frac{1.5318 - 1.5140}{1.5170 - 1} = \frac{0.0178}{0.5170} \approx 0.034$For flint glass:$\omega_{	ext{flint}} = \frac{1.6852 - 1.6434}{1.6499 - 1} = \frac{0.0418}{0.6499} \approx 0.064$Thus,the dispersive powers are $0.034$ and $0.064$ respectively.

If the refractive indices of crown glass for red,yellow,and violet colours are $1.5140, 1.5170$,and $1.5318$ respectively,and for flint glass these are $1.6434, 1.6499$,and $1.6852$ respectively,then the dispersive powers for crown and flint glass are respectively:

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