If the roots of $ax^2 + bx + c = 0$ are $\alpha, \beta$ and the roots of $Ax^2 + Bx + C = 0$ are $\alpha - k, \beta - k$,then $\frac{B^2 - 4AC}{b^2 - 4ac}$ is equal to

  • A
    $0$
  • B
    $1$
  • C
    $(\frac{A}{a})^2$
  • D
    $(\frac{a}{A})^2$

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