If the roots of the equation $3x^2 + 4kx + 3 = 0$ are non-real,then $k$ lies in the interval

  • A
    $[-2, -3/2]$
  • B
    $[3/2, 2]$
  • C
    $(-3/2, 3/2)$
  • D
    $(2, 3)$

Explore More

Similar Questions

If $a < b < c < d$,then what is the nature of the roots of the equation $(x - a)(x - c) + 2(x - b)(x - d) = 0$?

Difficult
View Solution

The solution of the equation $2x^3 - x^2 - 22x - 24 = 0$,given that two of the roots are in the ratio $3:4$,is:

Let $\alpha, \beta$ be two roots of the quadratic equation $x^2+ax-b=0, b \neq 0$. If the straight line $x \cos \theta + y \sin \theta = c$ touches the curve $(\frac{x}{\alpha})^n + (\frac{y}{\beta})^n = 2$ at the point $(\alpha, \beta)$, then $(\frac{a}{b})^2 + \frac{2}{b} =$

If the roots of $4x^2 + px + 9 = 0$ are equal,then the absolute value of $p$ is:

The roots of the equation $x^{2/3} + x^{1/3} - 2 = 0$ are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo