If the sets A and B are defined as A = { (x, | vedclass

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(C) The set $A$ represents the graph of the exponential function $y = e^x$. The set $B$ represents the graph of the linear function $y = x$.For any re

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$A \cap B = \phi$

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(C) The set $A$ represents the graph of the exponential function $y = e^x$. The set $B$ represents the graph of the linear function $y = x$.For any real number $x$,it is a known property that $e^x > x$. Specifically,the function $f(x) = e^x - x$ has a minimum value of $1$ at $x = 0$,meaning $e^x - x \ge 1$ for all $x \in R$.Since $e^x$ is never equal to $x$ for any $x \in R$,there are no common points between the two sets.Therefore,$A \cap B = \phi$.

If the sets $A$ and $B$ are defined as $A = \{ (x, y) : y = e^x, x \in R \}$ and $B = \{ (x, y) : y = x, x \in R \}$,then

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