If the sides of a triangle vary slightly in such a way that its circumradius remains constant,then $\frac{da}{\cos A} + \frac{db}{\cos B} + \frac{dc}{\cos C}$ is equal to

  • A
    $6R$
  • B
    $2R(dA + dB + dC)$
  • C
    $0$
  • D
    Both $(B)$ and $(C)$

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