If the sides of a triangular field are 290 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The sides of the triangle are $a = 290 \, m$,$b = 290 \, m$,and $c = 400 \, m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2} =

Vedclass · Accepted Answer

$42000$

Vedclass · Answer

(C) The sides of the triangle are $a = 290 \, m$,$b = 290 \, m$,and $c = 400 \, m$.First,calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2} = \frac{290 + 290 + 400}{2} = \frac{980}{2} = 490 \, m$.Using Heron's formula,Area = $\sqrt{s(s-a)(s-b)(s-c)}$.Area = $\sqrt{490(490-290)(490-290)(490-400)}$.Area = $\sqrt{490 	imes 200 	imes 200 	imes 90}$.Area = $\sqrt{490 	imes 90 	imes 200^2}$.Area = $200 	imes \sqrt{44100}$.Area = $200 	imes 210 = 42000 \, m^2$.

If the sides of a triangular field are $290 \, m$,$290 \, m$,and $400 \, m$,find the area of the field in $m^2$.

Similar Questions

The sides of $\Delta PQR$ measure $13 \, cm$, $14 \, cm$, and $15 \, cm$. Find its area in $cm^2$.

The sides of a triangle measure $12 \ cm$,$35 \ cm$,and $37 \ cm$. Find the area of the triangle. (in $cm^2$)

$A$ field is shaped like an equilateral triangle. Its length is $120 \, m$ on each side. Calculate its area using Heron's formula.

$A$ design is made on a rectangular tile of dimensions $50\, cm \times 70\, cm$ as shown in the figure. The design shows $8$ triangles,each with sides $26\, cm, 17\, cm$,and $25\, cm$. Find the total area of the design and the remaining area of the tile.

The area of an equilateral triangle with side $2 \sqrt{3} \, cm$ is (in $cm^2$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module