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(C) Let the sides of the triangle be $a = 13$,$b = 14$,and $c = 15$.The semi-perimeter $s$ is given by $s = \frac{a + b + c}{2} = \frac{13 + 14 + 15}{

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(C) Let the sides of the triangle be $a = 13$,$b = 14$,and $c = 15$.The semi-perimeter $s$ is given by $s = \frac{a + b + c}{2} = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21$.The area of the triangle $\Delta$ using Heron's formula is $\Delta = \sqrt{s(s - a)(s - b)(s - c)}$.$\Delta = \sqrt{21(21 - 13)(21 - 14)(21 - 15)} = \sqrt{21 	imes 8 	imes 7 	imes 6}$.$\Delta = \sqrt{7056} = 84$.The radius of the incircle $r$ is given by $r = \frac{\Delta}{s}$.$r = \frac{84}{21} = 4$.

If the sides of a triangle are $13, 14, 15$,then the radius of its incircle is

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