If the statement p vee sim(q wedge r) is fals | vedclass

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(C) The statement $p \vee \sim(q \wedge r)$ is false if and only if both components of the disjunction are false.Therefore,$p = F$ and $\sim(q \wedge

Vedclass · Accepted Answer

$F, T, T$

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(C) The statement $p \vee \sim(q \wedge r)$ is false if and only if both components of the disjunction are false.Therefore,$p = F$ and $\sim(q \wedge r) = F$.Since $\sim(q \wedge r) = F$,it implies $(q \wedge r) = T$.For the conjunction $(q \wedge r)$ to be true,both $q$ and $r$ must be true.Thus,$q = T$ and $r = T$.So,the truth values are $p = F, q = T, r = T$.

If the statement $p \vee \sim(q \wedge r)$ is false,then the truth values of $p, q$ and $r$ are respectively:

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