If the sum of the slopes of the lines represe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The equation of the pair of lines is $x^2 - 2xy 	an 	heta - y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 1

Vedclass · Accepted Answer

$	an^{-1}(-2)$

Vedclass · Answer

(D) The equation of the pair of lines is $x^2 - 2xy 	an 	heta - y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 1$,$2h = -2 	an 	heta$,and $b = -1$.The sum of the slopes $m_1 + m_2$ is given by the formula $\frac{-2h}{b}$.Substituting the values,we have $m_1 + m_2 = \frac{-(-2 	an 	heta)}{-1} = -2 	an 	heta$.Given that the sum of the slopes is $4$,we set $-2 	an 	heta = 4$.This simplifies to $	an 	heta = -2$.Therefore,$	heta = 	an^{-1}(-2)$.

If the sum of the slopes of the lines represented by $x^2 - 2xy \tan \theta - y^2 = 0$ is $4$,then $\theta =$

Similar Questions

The joint equation of a pair of straight lines passing through the origin and having slopes $(1+\sqrt{2})$ and $\left(\frac{1}{1+\sqrt{2}}\right)$ is $......$

Find the equation of the pair of lines passing through the origin and perpendicular to the pair of lines given by $5x^2 - 7xy - 3y^2 = 0$.

The equations of the lines represented by the equation ${x^2} - 5xy + 6{y^2} = 0$ are

If $2x^2 + 3xy - 2y^2 - 5x + fy - 3 = 0$ represents a pair of straight lines,then one of the possible values of $f$ is

The product of the perpendicular distances from the origin to the pair of straight lines $12x^2 + 25xy + 12y^2 + 10x + 11y + 2 = 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module