If the truth value of the compound statement | vedclass

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(A) Step $1$: The implication $A 	o B$ is false only when $A$ is true and $B$ is false.Step $2$: Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r

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$(F, T)$

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(A) Step $1$: The implication $A 	o B$ is false only when $A$ is true and $B$ is false.Step $2$: Here, $A = [(p \lor q) \land (q 	o r) \land (\sim r)]$ and $B = (p \land q)$.Step $3$: For $B = (p \land q)$ to be false, at least one of $p$ or $q$ must be false.Step $4$: For $A$ to be true, $(p \lor q)$ must be true, $(q 	o r)$ must be true, and $(\sim r)$ must be true.Step $5$: From $(\sim r) = T$, we get $r = F$.Step $6$: Since $(q 	o r) = T$ and $r = F$, $q$ must be false.Step $7$: Since $(p \lor q) = T$ and $q = F$, $p$ must be true.Step $8$: Now, evaluate $p 	o q$: $T 	o F = F$.Step $9$: Evaluate $q 	o p$: $F 	o T = T$.Step $10$: The truth values are $(F, T)$.

If the truth value of the compound statement $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then the truth values of $p \to q$ and $q \to p$ are respectively...

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