If the vertices of a triangle are (-2, 6),(3, | vedclass

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(B) Given vertices of the triangle are $(x_1, y_1) = (-2, 6)$,$(x_2, y_2) = (3, -6)$,and $(x_3, y_3) = (1, 5)$.The area of a triangle with vertices $(

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$15.5$ sq. units

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(B) Given vertices of the triangle are $(x_1, y_1) = (-2, 6)$,$(x_2, y_2) = (3, -6)$,and $(x_3, y_3) = (1, 5)$.The area of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the determinant formula:$	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Substituting the values:$	ext{Area} = \frac{1}{2} |-2(-6 - 5) + 3(5 - 6) + 1(6 - (-6))|$$	ext{Area} = \frac{1}{2} |-2(-11) + 3(-1) + 1(12)|$$	ext{Area} = \frac{1}{2} |22 - 3 + 12|$$	ext{Area} = \frac{1}{2} |31| = 15.5 	ext{ sq. units}$

If the vertices of a triangle are $(-2, 6)$,$(3, -6)$,and $(1, 5)$,then the area of the triangle is

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