If the wavelength for an electron emitted fro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The kinetic energy $K$ of the emitted electron is given by the de Broglie wavelength formula: $\lambda = \frac{h}{\sqrt{2mK}}$.Rearranging for $K$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The kinetic energy $K$ of the emitted electron is given by the de Broglie wavelength formula: $\lambda = \frac{h}{\sqrt{2mK}}$.Rearranging for $K$: $K = \frac{h^2}{2m\lambda^2}$.Substituting the given values: $K = \frac{(6.626 	imes 10^{-34})^2}{2 	imes 9.1 	imes 10^{-31} 	imes (3.3 	imes 10^{-10})^2} \approx 2.215 	imes 10^{-18} \ J$.The minimum energy required to escape from the ground state of $H$ atom is the ionization energy: $E_{req} = 13.6 \ eV = 13.6 	imes 1.602 	imes 10^{-19} \ J \approx 2.179 	imes 10^{-18} \ J$.The total energy absorbed is $E_{abs} = E_{req} + K$.The ratio is $\frac{E_{abs}}{E_{req}} = 1 + \frac{K}{E_{req}} = 1 + \frac{2.215 	imes 10^{-18}}{2.179 	imes 10^{-18}} \approx 1 + 1.016 = 2.016$.Rounding to the nearest integer,the value is $2$.

Column-$I$	Column-$II$
$(1)$ Photon	$(A)$ Value of $4$ for $N$ shell
$(2)$ Electron	$(B)$ Probability density
$(3)$ $\psi^2$	$(C)$ Always $+$ value
$(4)$ Principal quantum number $(n)$	$(D)$ Represents wavelength and momentum

Similar Questions

Which of the following graphs represents one node?

The shape of the probability distribution curve for the $2s$ orbital is .........

Which of the following statements is $CORRECT$?

Match the following columns:

Column-$I$ Column-$II$

$(1)$ Photon $(A)$ Value of $4$ for $N$ shell

$(2)$ Electron $(B)$ Probability density

$(3)$ $\psi^2$ $(C)$ Always $+$ value

$(4)$ Principal quantum number $(n)$ $(D)$ Represents wavelength and momentum

Vedclass Test Series

Exam Paper Generator

Online Exam Module