(D) The equivalent capacitance of two capacitors of $1\,\mu F$ connected in series is given by $\frac{1}{C_s} = \frac{1}{1} + \frac{1}{1} = 2$,so $C_s

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Two of them are in series and then connected in parallel to the third

(D) The equivalent capacitance of two capacitors of $1\,\mu F$ connected in series is given by $\frac{1}{C_s} = \frac{1}{1} + \frac{1}{1} = 2$,so $C_s = 0.5\,\mu F$.When this combination is connected in parallel with the third capacitor of $1\,\mu F$,the total equivalent capacitance is $C_{eq} = C_s + 1\,\mu F = 0.5\,\mu F + 1\,\mu F = 1.5\,\mu F$.Therefore,the correct configuration is that two capacitors are in series and then connected in parallel to the third.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

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If three capacitors each of capacity $1\,\mu F$ are connected in such a way that the resultant capacity is $1.5\,\mu F$,then

A
All the three are connected in series
B
All the three are connected in parallel
C
Two of them are in parallel and connected in series to the third
D
Two of them are in series and then connected in parallel to the third

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Class 12

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

The total charge on the system of capacitors with capacitances $C_{1} = 1\,\mu F$,$C_{2} = 2\,\mu F$,$C_{3} = 4\,\mu F$,and $C_{4} = 3\,\mu F$ connected in parallel is $......\,\mu C$. (Assume a battery of $20\,V$ is connected to the combination.)

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The effective capacitance between $A$ and $B$ in the given figure is:

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$A$ number of capacitors,each of capacitance $1\,\mu F$ and each of which gets punctured if a potential difference exceeding $500\,V$ is applied,are provided. An arrangement suitable for giving a capacitance of $2\,\mu F$ across which $3000\,V$ may be applied requires at least:

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The minimum number of capacitors of $2\,\mu F$ capacitance each required to obtain a resultant capacitance of $5\,\mu F$ is

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In the connections shown in the adjoining figure,the equivalent capacitance between $A$ and $B$ will be......$\mu F$.

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If three capacitors each of capacity $1\,\mu F$ are connected in such a way that the resultant capacity is $1.5\,\mu F$,then

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The total charge on the system of capacitors with capacitances $C_{1} = 1\,\mu F$,$C_{2} = 2\,\mu F$,$C_{3} = 4\,\mu F$,and $C_{4} = 3\,\mu F$ connected in parallel is $......\,\mu C$. (Assume a battery of $20\,V$ is connected to the combination.)

The effective capacitance between $A$ and $B$ in the given figure is:

$A$ number of capacitors,each of capacitance $1\,\mu F$ and each of which gets punctured if a potential difference exceeding $500\,V$ is applied,are provided. An arrangement suitable for giving a capacitance of $2\,\mu F$ across which $3000\,V$ may be applied requires at least:

The minimum number of capacitors of $2\,\mu F$ capacitance each required to obtain a resultant capacitance of $5\,\mu F$ is

In the connections shown in the adjoining figure,the equivalent capacitance between $A$ and $B$ will be......$\mu F$.

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