(C) Let $n$ be the number of capacitors in each series branch and $m$ be the number of such parallel branches.For each series branch,the total potenti

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(C) Let $n$ be the number of capacitors in each series branch and $m$ be the number of such parallel branches.For each series branch,the total potential difference is $V_{total} = n \times V_{max} = n \times 500 = 3000\,V$.Thus,$n = 3000 / 500 = 6$.The equivalent capacitance of one series branch is $C_s = (1\,\mu F) / n = 1/6\,\mu F$.For $m$ such branches in parallel,the total capacitance is $C_{eq} = m \times C_s = m \times (1/6) = 2\,\mu F$.Solving for $m$,we get $m = 2 \times 6 = 12$.The total number of capacitors required is $N = n \times m = 6 \times 12 = 72$.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

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$A$ number of capacitors,each of capacitance $1\,\mu F$ and each of which gets punctured if a potential difference exceeding $500\,V$ is applied,are provided. An arrangement suitable for giving a capacitance of $2\,\mu F$ across which $3000\,V$ may be applied requires at least:

A
$18$ component capacitors
B
$36$ component capacitors
C
$72$ component capacitors
D
$144$ component capacitors

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Class 12 Questions

Class 12

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

In the given figure,the equivalent capacitance $C_{AB}$ is equal to ...... $C$.

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The equivalent capacitance of three capacitors of capacitance $C_1, C_2$ and $C_3$ connected in parallel is $12$ units and their product is $C_1 \cdot C_2 \cdot C_3 = 48$. When the capacitors $C_1$ and $C_2$ are connected in parallel,the equivalent capacitance is $6$ units. Then the capacitances are:

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When three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)

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Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

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Three capacitors $C_1$,$C_2$,and $C_3$ are connected in parallel,and their equivalent capacitance is $12$ units. Given $C_1 \cdot C_2 \cdot C_3 = 48$ units. When $C_1$ and $C_2$ are connected in parallel,their equivalent capacitance is $6$ units. Find the individual capacitances $C_1, C_2, C_3$.

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$A$ number of capacitors,each of capacitance $1\,\mu F$ and each of which gets punctured if a potential difference exceeding $500\,V$ is applied,are provided. An arrangement suitable for giving a capacitance of $2\,\mu F$ across which $3000\,V$ may be applied requires at least:

Similar Questions

In the given figure,the equivalent capacitance $C_{AB}$ is equal to ...... $C$.

When three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)

Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

Three capacitors $C_1$,$C_2$,and $C_3$ are connected in parallel,and their equivalent capacitance is $12$ units. Given $C_1 \cdot C_2 \cdot C_3 = 48$ units. When $C_1$ and $C_2$ are connected in parallel,their equivalent capacitance is $6$ units. Find the individual capacitances $C_1, C_2, C_3$.

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