If travelling at equal speeds,the longest wav | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = h / p = h / (mv)$,where $h$ is Planck's constant,$m$ is the m

Vedclass · Accepted Answer

electron

Vedclass · Answer

(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = h / p = h / (mv)$,where $h$ is Planck's constant,$m$ is the mass,and $v$ is the velocity.Since the speed $v$ is constant for all particles,the wavelength $\lambda$ is inversely proportional to the mass $m$ of the particle $(\lambda \propto 1/m)$.Comparing the masses: $m_{	ext{electron}} Since the electron has the smallest mass,it will have the longest wavelength.

If travelling at equal speeds,the longest wavelength of the following matter waves is that for a :

Similar Questions

$A$ cricket ball of $0.5 \ kg$ is moving with a velocity of $100 \ m/s$. The wavelength associated with its motion is

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$ and its mass is $9.1 \times 10^{-31} \ kg$. Calculate the velocity,momentum,and wavelength of the electron.

The wavelength of a microscopic particle of mass $9.1 \times 10^{-31} \ kg$ is $182 \ nm$. Its kinetic energy in $J$ is: $(h = 6.625 \times 10^{-34} \ J \ s)$

The de Broglie wavelength of an electron travelling with $20 \%$ of velocity of light is
$(h = 6.626 \times 10^{-34} \ J \ s; m_{e} = 9.1 \times 10^{-31} \ kg)$

The wavelength of a photon is $5200 \ \mathring{A}$. At what velocity will an electron have the same wavelength as this photon (in $m/s$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module