The wavelength of a photon is 5200 mathring{ | vedclass

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(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.For an electron,the velocity $v$ is given by $v

Vedclass · Accepted Answer

$1400$

Vedclass · Answer

(A) According to the de Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.For an electron,the velocity $v$ is given by $v = \frac{h}{m \lambda}$.Given: $h = 6.626 	imes 10^{-34} \ J \cdot s$,$m = 9.11 	imes 10^{-31} \ kg$,and $\lambda = 5200 \ \mathring{A} = 5.2 	imes 10^{-7} \ m$.Substituting the values:$v = \frac{6.626 	imes 10^{-34}}{(9.11 	imes 10^{-31}) 	imes (5.2 	imes 10^{-7})}$$v = \frac{6.626 	imes 10^{-34}}{47.372 	imes 10^{-38}}$$v = 0.1398 	imes 10^4 \ m/s \approx 1400 \ m/s$.

The wavelength of a photon is $5200 \ \mathring{A}$. At what velocity will an electron have the same wavelength as this photon (in $m/s$)?

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