If we multiply a fraction by itself and divide the product by the square of its reciprocal,the fraction obtained is $3 \frac{13}{81}$. The original fraction is

  • A
    $\frac{16}{9}$
  • B
    $\frac{8}{9}$
  • C
    $\frac{4}{3}$
  • D
    $\frac{1}{3}$

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Similar Questions

If $(a+\frac{1}{a})^{2}=3,$ then $a^{3}+\frac{1}{a^{3}}=?$

Which of the following is true?
$I.$ $\frac{1}{\sqrt[3]{12}} > \frac{1}{\sqrt[4]{29}} > \frac{1}{\sqrt{5}}$
$II.$ $\frac{1}{\sqrt[4]{29}} > \frac{1}{\sqrt[3]{12}} > \frac{1}{\sqrt{5}}$
$III.$ $\frac{1}{\sqrt{5}} > \frac{1}{\sqrt[3]{12}} > \frac{1}{\sqrt[4]{29}}$
$IV.$ $\frac{1}{\sqrt{5}} > \frac{1}{\sqrt[4]{29}} > \frac{1}{\sqrt[3]{12}}$

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If we multiply a fraction by itself and divide the product by its reciprocal,the fraction thus obtained is $18 \frac{26}{27}$. The fraction is

If $10^{2y} = 25$,then what is the value of $10^{y}$?

What approximate value will come in place of the question mark $(?)$ in the given equation? (You are not expected to calculate the exact value)
$2775 \times \frac{160}{\sqrt{?}} = 5550$

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