Imagine removing one electron from $He^4$ and $He^3$. Their energy levels,as worked out on the basis of the Bohr model,will be very close. Explain why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Both ${ }_{2} He^{3}$ and ${ }_{2} He^{4}$ are isotopes of helium.
When one electron is removed from each,they both become hydrogen-like ions $(He^+)$ with a single electron.
The energy levels of a hydrogen-like ion are given by the formula $E_n = -\frac{Z^2 R_y}{n^2}$,where $Z$ is the atomic number and $R_y$ is the Rydberg constant.
Since both isotopes have the same atomic number $Z = 2$,their energy levels are identical in the ideal Bohr model.
However,the slight difference in mass between the nuclei of $He^3$ and $He^4$ leads to a very small difference in the reduced mass of the electron-nucleus system,which is why their energy levels are very close but not perfectly identical.

Explore More

Similar Questions

Mention the value of the Rydberg constant with its unit.

In the Bohr model of the hydrogen atom, the electron is pictured to rotate in a circular orbit of radius $5 \times 10^{-11} \, m$, at a speed of $2.2 \times 10^{6} \, m/s$. What is the current associated with the electron's motion (in $ \, mA$)?

$A$ diatomic molecule is made of two masses $m_1$ and $m_2$ which are separated by a distance $r$. If we calculate its rotational energy by applying Bohr's rule of angular momentum quantization,its energy will be given by: ($n$ is an integer)

$A$ small particle of mass $m$ moves in such a way that its potential energy $U = \frac{1}{2} m \omega^2 r^2$,where $\omega$ is a constant and $r$ is the distance of the particle from the origin. Assuming Bohr's quantization of angular momentum and a circular orbit,the radius of the $n^{\text{th}}$ orbit will be proportional to:

$A$ hydrogen-like atom of atomic number $Z$ is in an excited state of quantum number $2n$. It can emit a maximum energy photon of $204 \ eV$. If it makes a transition to quantum state $n$,a photon of energy $40.8 \ eV$ is emitted. The value of $n$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo