In KO_2,the nature of oxygen species and the | vedclass

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(B) In $KO_2$,the nature of oxygen species is superoxide (superoxide ion is $O_2^-$).To calculate the oxidation state of oxygen,let $x$ be the oxidati

Vedclass · Accepted Answer

Superoxide and $-1/2$

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(B) In $KO_2$,the nature of oxygen species is superoxide (superoxide ion is $O_2^-$).To calculate the oxidation state of oxygen,let $x$ be the oxidation state of oxygen.The oxidation state of $K$ is $+1$.Applying the rule for the sum of oxidation states in a neutral molecule:$+1 + 2(x) = 0$$2x = -1$$x = -\frac{1}{2}$Thus,the oxidation state of oxygen in $KO_2$ is $-\frac{1}{2}$.

In $KO_2$,the nature of oxygen species and the oxidation state of oxygen atom are,respectively

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