What is the correct order of decreasing oxida | vedclass

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(B) To determine the oxidation state of iodine $(I)$ in each compound:$1$. In $HIO_4$: Let the oxidation state of $I$ be $x$. $1 + x + 4(-2) = 0 \impl

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$HIO_4, ICl_5, I_2, HI$

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(B) To determine the oxidation state of iodine $(I)$ in each compound:$1$. In $HIO_4$: Let the oxidation state of $I$ be $x$. $1 + x + 4(-2) = 0 \implies x = +7$.$2$. In $ICl_5$: Let the oxidation state of $I$ be $x$. $x + 5(-1) = 0 \implies x = +5$.$3$. In $I_2$: The oxidation state of iodine in its elemental form is $0$.$4$. In $HI$: Let the oxidation state of $I$ be $x$. $1 + x = 0 \implies x = -1$.Thus,the decreasing order of oxidation states is $+7 (HIO_4) > +5 (ICl_5) > 0 (I_2) > -1 (HI)$.

List $I$ (Compound)	List $II$ (Oxidation state of $N$)
$(A)$ $NO_2$	$(1)$ $+5$
$(B)$ $HNO$	$(2)$ $-3$
$(C)$ $NH_3$	$(3)$ $+4$
$(D)$ $N_2O_5$	$(4)$ $+1$

What is the correct order of decreasing oxidation state of iodine in the following compounds?

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