In the given figure,if $\angle D = \angle C$,then is it true that $\triangle ADE \sim \triangle ACB$? Why?
(N/A) Yes,it is true.
In $\triangle ADE$ and $\triangle ACB$:
$1$. $\angle A = \angle A$ (Common angle in both triangles).
$2$. $\angle D = \angle C$ (Given in the problem).
Therefore,by the $AA$ similarity criterion,$\triangle ADE \sim \triangle ACB$.
In $\triangle ADE$ and $\triangle ACB$:
$1$. $\angle A = \angle A$ (Common angle in both triangles).
$2$. $\angle D = \angle C$ (Given in the problem).
Therefore,by the $AA$ similarity criterion,$\triangle ADE \sim \triangle ACB$.
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