In Delta PQR and Delta XYZ,if angle P = angle | vedclass

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(C) Given that in $\Delta PQR$ and $\Delta XYZ$:$1$. $\angle P = \angle Z$$2$. $\angle Q = \angle Y$$3$. $PQ = YZ$By the $ASA$ (Angle-Side-Angle) cong

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$ZYX$

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(C) Given that in $\Delta PQR$ and $\Delta XYZ$:$1$. $\angle P = \angle Z$$2$. $\angle Q = \angle Y$$3$. $PQ = YZ$By the $ASA$ (Angle-Side-Angle) congruence criterion,the correspondence must match the vertices in the same order.Since $\angle P$ corresponds to $\angle Z$,$\angle Q$ corresponds to $\angle Y$,and the side $PQ$ corresponds to $ZY$ (or $YZ$),the remaining vertex $R$ must correspond to $X$.Therefore,the correspondence is $P \leftrightarrow Z$,$Q \leftrightarrow Y$,and $R \leftrightarrow X$.Thus,$\Delta PQR \cong \Delta ZYX$.

In $\Delta PQR$ and $\Delta XYZ$,if $\angle P = \angle Z$,$\angle Q = \angle Y$,and $PQ = YZ$,then $\Delta PQR \cong \Delta \ldots \ldots \ldots$

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