In Delta XYZ and Delta MNO,frac{XY}{MN} = fra | vedclass

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(A) Given the ratio of the sides of the two triangles: $\frac{XY}{MN} = \frac{XZ}{NO} = \frac{YZ}{MO}$.According to the $SSS$ (Side-Side-Side) similar

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$XYZ \leftrightarrow MNO$

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(A) Given the ratio of the sides of the two triangles: $\frac{XY}{MN} = \frac{XZ}{NO} = \frac{YZ}{MO}$.According to the $SSS$ (Side-Side-Side) similarity criterion,if the sides of two triangles are proportional,then the triangles are similar.By observing the ratios:$XY$ corresponds to $MN$$XZ$ corresponds to $NO$$YZ$ corresponds to $MO$Therefore,the vertices must correspond in the same order: $X \leftrightarrow M$,$Y \leftrightarrow N$,and $Z \leftrightarrow O$.Thus,the correspondence is $\Delta XYZ \sim \Delta MNO$.

In $\Delta XYZ$ and $\Delta MNO$,$\frac{XY}{MN} = \frac{XZ}{NO} = \frac{YZ}{MO}$. Then,the correspondence $\ldots$ is a similarity.

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