In $L-C$ oscillation,the maximum charge on the capacitor is $Q$. If at any instant,the electric energy and magnetic energy associated with the circuit are equal,then the charge on the capacitor at that instant is:

Consider an $LC$ circuit,with inductance $L = 0.1 \ H$ and capacitance $C = 10^{-3} \ F$,kept on a plane. The area of the circuit is $1 \ m^2$. It is placed in a constant magnetic field of strength $B_0$ which is perpendicular to the plane of the circuit. At time $t = 0$,the magnetic field strength starts increasing linearly as $B = B_0 + \beta t$ with $\beta = 0.04 \ T \ s^{-1}$. The maximum magnitude of the current in the circuit is . . . . $mA$.

$A$ series resonant $AC$ circuit contains a capacitance $10^{-6} \,F$ and an inductor of $10^{-4} \,H$. The frequency of electrical oscillations will be

The natural frequency of an $L-C$ circuit is $1,25,000 \text{ cycle/s}$. Then the capacitor $C$ is replaced by another capacitor with a dielectric medium of dielectric constant $K$. In this case,the frequency decreases by $25 \text{ kHz}$. The value of $K$ is

$A$ $4 \mu F$ capacitor is charged to $10 \ V$. The battery is then disconnected and a pure $10 \ mH$ coil is connected across the capacitor so that $LC$ oscillations are set up. The maximum current in the coil is (in $A$)

What are $LC$ oscillations?