In DNA,20 % of the bases are adenine. What pe | vedclass

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(C) According to Chargaff's rule,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amount of guanine $(G)$ is equal to the a

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$50$

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(C) According to Chargaff's rule,the amount of adenine $(A)$ is equal to the amount of thymine $(T)$,and the amount of guanine $(G)$ is equal to the amount of cytosine $(C)$.Given that adenine $(A)$ = $20 \%$,then thymine $(T)$ must also be $20 \%$.The total percentage of purines $(A + G)$ or pyrimidines $(T + C)$ in a $DNA$ molecule is always $50 \%$.Since $T + C = 50 \%$ and we know $T = 20 \%$,we can calculate $C = 50 \% - 20 \% = 30 \%$.Therefore,the total percentage of pyrimidines $(T + C)$ is $20 \% + 30 \% = 50 \%$.

In $DNA$,$20 \%$ of the bases are adenine. What percentage of bases are pyrimidines (in $\%$)?

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