In $\triangle ABC$,with usual notations,if $\frac{1}{b+c}+\frac{1}{c+a}=\frac{3}{a+b+c}$,then $m \angle C$ is equal to

  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{2}$
  • C
    $\frac{\pi}{4}$
  • D
    $\frac{\pi}{6}$

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