In $\triangle ABC$,if $\left|\begin{array}{lll}a & b & c \\ b & c & a \\ c & a & b\end{array}\right|=0$,then $\cos A \cos B+\cos B \cos C+\cos C \cos A=$

  • A
    -$1$
  • B
    $\frac{3}{4}$
  • C
    $\frac{9}{4}$
  • D
    $1$

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