In YDSE,the source S placed symmetrically wit | vedclass

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(D) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength,$D$ is the distance between the s

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the fringe width will remain same but the fringe pattern will shift down.

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(D) The fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits. Since $\lambda$,$D$,and $d$ remain unchanged,the fringe width $\beta$ remains constant.When the source $S$ is moved closer to the upper slit $S_1$,the path length from $S$ to $S_1$ becomes shorter than the path length from $S$ to $S_2$. To maintain a zero path difference at the screen,the point on the screen must be closer to $S_2$ than to $S_1$. This means the central bright fringe (where path difference is zero) shifts downwards. Consequently,the entire fringe pattern shifts downwards.

In $YDSE$,the source $S$ placed symmetrically with respect to the slits $S_1$ and $S_2$ is now moved parallel to the plane of the slits so that it is closer to the upper slit $S_1$,as shown. Then,

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In $YDSE$, a thin film $(\mu=1.6)$ of thickness $0.01 \,mm$ is introduced in the path of one of the two interfering beams. The central fringe moves to a position occupied by the $10^{\text{th}}$ bright fringe earlier. The wavelength of the wave is ......... $\mathring{A}$.

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