In a 500, m race,the ratio of the speeds of t | vedclass

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(B) The total length of the race is $500\, m$.$A$ is given a start of $140\, m$,which means $A$ only needs to cover $500 - 140 = 360\, m$ to reach the

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$50$

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(B) The total length of the race is $500\, m$.$A$ is given a start of $140\, m$,which means $A$ only needs to cover $500 - 140 = 360\, m$ to reach the finish line.The ratio of the speeds of $A$ and $B$ is $4:5$. This means that for every $4\, m$ covered by $A$,$B$ covers $5\, m$.When $A$ covers $360\, m$,the distance covered by $B$ is calculated as: $\frac{5}{4} 	imes 360 = 450\, m$.Since $B$ covers $450\, m$ in the same time that $A$ covers $360\, m$ (reaching the finish line),$B$ is still $500 - 450 = 50\, m$ away from the finish line.Therefore,$A$ wins the race by $50\, m$.

In a $500\, m$ race,the ratio of the speeds of two contestants $A$ and $B$ is $4:5$. $A$ has a start of $140\, m$. Then $A$ wins by (in $m$):

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