In a $\triangle ABC$,$\sin A$ and $\sin B$ satisfy the equation $c^2 x^2 - c(a+b)x + ab = 0$. Then:

  • A
    the triangle is acute-angled
  • B
    the triangle is obtuse-angled
  • C
    $\sin C = \frac{\sqrt{3}}{2}$
  • D
    $\sin A + \cos A = \frac{a+b}{c}$

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