In a $\triangle ABC$,if $4a = b + c$,then $\tan \frac{B}{2} \tan \frac{C}{2} =$

  • A
    $\frac{1}{3}$
  • B
    $\frac{3}{5}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{1}{2}$

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