In a balanced equation $H_2SO_4 + x \ HI \to H_2S + y \ I_2 + z \ H_2O$,the values of $x, y, z$ are

  • A
    $x = 3, y = 5, z = 2$
  • B
    $x = 4, y = 8, z = 5$
  • C
    $x = 8, y = 4, z = 4$
  • D
    $x = 5, y = 3, z = 4$

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From the given reaction:
$2 KMnO_4 + 3 H_2 SO_4 + 5 H_2 O_2 \longrightarrow K_2 SO_4 + 2 MnSO_4 + 8 H_2 O + 5 O_2$
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$(Molar \ mass \ of \ KMnO_4 = 158 \ g \ mol^{-1})$

In the reaction $2[Fe(CN)_6]^{3-} + H_2O_2 + 2OH^{-} \rightarrow 2[Fe(CN)_6]^{4-} + 2H_2O + O_2$,what is the equivalent weight of the reductant? $(Fe = 56, C = 12, N = 14, O = 16, H = 1)$

$A$ $20.0 \,mL$ solution containing $0.2 \,g$ impure $H_2O_2$ reacts completely with $0.316 \,g$ of $KMnO_4$ in acidic solution. The purity of $H_2O_2$ (in $\%$) is........... (mol. wt. of $H_2O_2 = 34$; mol. wt. of $KMnO_4 = 158$)

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