In a book of $500$ pages, it is found that there are $250$ typing errors. Assume that Poisson law holds for the number of errors per page. Then, the probability that a random sample of $2$ pages will contain no error, is:
- A$e^{-0.3}$
- B$e^{-0.5}$
- C$e^{-1}$
- D$e^{-2}$
Explore More
Similar Questions
Let a random variable $X$ take values $\{0, 1, 2, 3\}$ with $P(X=0) = P(X=1) = p$,$P(X=2) = P(X=3) = q$,and $E(X^2) = 2E(X)$. Then the value of $8p - 1$ is:
DifficultJEE MAIN 2025
View SolutionIf $X$ is a random variable with the distribution given below:
$X = x_i$ $0$ $1$ $2$ $3$ $P(X = x_i)$ $k$ $3k$ $3k$ $k$
Then the value of $k$ and its variance are respectively given by:
| $X = x_i$ | $0$ | $1$ | $2$ | $3$ |
| $P(X = x_i)$ | $k$ | $3k$ | $3k$ | $k$ |
Then the value of $k$ and its variance are respectively given by:
If a random variable $X$ follows a Poisson distribution with a mean value of $5$,then the probability that $X < 3$ is:
Find the variance of the number obtained on a throw of a fair die.
Medium
View SolutionFor the random variable $X$ with the probability distribution given by the table:
$X = x$ $0$ $1$ $2$ $3$ $P(X = x)$ $K$ $K + \frac{1}{7}$ $2K$ $\frac{2}{5}$
The mean of $X$ is:
| $X = x$ | $0$ | $1$ | $2$ | $3$ |
| $P(X = x)$ | $K$ | $K + \frac{1}{7}$ | $2K$ | $\frac{2}{5}$ |
The mean of $X$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo