In a circle with radius $r,$ an arc subtends an angle of measure $\theta$ at the centre. Then,the area of the major sector is $=$ ..........

  • A
    $\frac{\pi r \theta}{180}$
  • B
    $2 \pi r - \frac{\pi r \theta}{180}$
  • C
    $\pi r^{2} - \frac{\pi r^{2} \theta}{360}$
  • D
    $\frac{\pi r^{2} \theta}{360}$

Explore More

Similar Questions

The union of a chord of a circle and its corresponding arc is called $\ldots \ldots \ldots \ldots$

In $\odot (P, 20)$,the area of a minor sector is $150\, cm^2$. The length of the arc corresponding to that sector is $\dots\, cm$.

The maximum area of a triangle inscribed in a semicircle with diameter $30 \, cm$ is $\ldots \ldots \ldots \, cm^{2}$.

The radius of a circle is $3.5\,cm$. The area of the minor sector formed by two perpendicular radii of that circle is $\ldots \ldots \ldots \,cm^2$.

The diameter of a circle with area $38.5 \, m^2$ is $\ldots \ldots \ldots \ldots m$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo