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(A) According to Graham's law of effusion,the rate of effusion of a gas is inversely proportional to the square root of its molar mass $(Rate \propto

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Hydrogen

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(A) According to Graham's law of effusion,the rate of effusion of a gas is inversely proportional to the square root of its molar mass $(Rate \propto 1/\sqrt{M})$.Since the molar mass of hydrogen $(M_{H_2} = 2 \ g/mol)$ is much smaller than the molar mass of carbon dioxide $(M_{CO_2} = 44 \ g/mol)$,the hydrogen gas will effuse out of the container faster.Alternatively,the root mean square speed $(v_{	ext{rms}})$ is given by $v_{	ext{rms}} = \sqrt{3RT/M}$. Since $v_{	ext{rms}} \propto 1/\sqrt{M}$,hydrogen has a higher $v_{	ext{rms}}$ than carbon dioxide at the same temperature,leading to a higher rate of effusion.

In a closed container,the same number of hydrogen $(H_2)$ and carbon dioxide $(CO_2)$ molecules are kept. If a small hole is made in the container,which gas will effuse out faster?

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